1. What will come in place of question mark in the following number series?
1 21 103 313 741 ?
1) 1501
2) 1504
3) 1512
4) 1523
5) None of these
2. In how many different ways can the letters of the word CYCLE be arranged?
1) 60
2) 120
3) 240
4) 30
5) 24
3. If the numerator of a fraction is increased by 260% and the denominator is decreased by 25% the resultant fraction is 3. What was the original fraction?
1) 3∕5
2) 5/8
3) 7/8
4) 5/6
5) 3/7
4. A train crosses a pole in 6.4 seconds and a 220-metres long-platform in 15.2 seconds. What is the speed of train?
1) 15 ms-1
2) 20 ms-1
3) 25 ms-1
4) 30 ms-1
5) 40 ms-1
5. Which is the largest among the given fractions? 17/24, 19/27, 5/9,11/15, 4/7
1) 17/24
2) 19/27
3) 5/9
4) 11/15
5) 4/7
Directions (Q.6-10): Study the pie chart along with the table to answer the given questions.
Distribution of number of students in standard fifth to tenth in a school.
Total number of students = 4500 
Ratio between number of boys and girls 
6. Total number of boys in standards sixth and seventh together is approximately what percent of the total number of boys in the school?
1) 38
2) 31
3) 30
4) 34
5) 39
7. What is the difference between total number of boys and total number of girls studying in all the standards together?
1) 242
2) 224
3) 244
4) 246
5) 252
8. What is the ratio between total number of boys in standards seventh and ninth together and the total number of girls in standards fifth and sixth together respectively?
1) 19 : 18
2) 16 : 15
3) 19 : 16
4) 19 : 17
5) 18 : 17
9. What is the ratio between number of girls in seventh standard and number of boys in tenth standard respectively?
1) 8 : 5
2) 9 : 7
3) 9 : 5
4) 4 : 3
5) 7 : 4
10. Total number of boys in standards fifth, sixth and seventh together is what percent of the total number of girls in standards eighth, ninth and tenth together? (rounded off to nearest integer)
1) 119
2) 117
3) 86
4) 114
5) 93
ANSWERS:
1. (1) The series is
2. (1) Number of ways
3. (2) Let the original fraction be
Now, new fraction
or,
4. (3) Let the speed of train be x ms–1 and length be y.
Now,
or, 32x = 5y ….. (i)
Again,
or, 5y + 1100 = 76x ….. (ii)
Solving eqn (i) and (ii), we get
x = 25 ms–1
5. (4)
(6-10)
6. (4) Required percent
7. (1) Required difference
= 2371 – 2129 = 242
8. (1) Required ratio
9. (2) Required ratio
10. (2) Required percent
