PROBLEMS BASED ON AGES:
If the current age is x, then age n years later/hence = x + n.
If the current age is x, then age n years ago = x – n.
If the sum of the ages of q persons is x, then n years later sum of the ages = x + nq
If the sum of the ages of q persons is x, then n years ago sum of the ages = x – nq
If the Average of the ages of q persons is x, then n years later average of the ages = x + n.
If the Average of the ages of q persons is x, then n years ago average of the ages = x – n.
SOME MODELS OF QUESTIONS
- Ifa:b= 2:3 andb:c= 5:7 thenfinda: b:c =?
(1)15 : 10 : 14
(2) 10 : 15 : 21
(3) 10: 15 : 14
(4) 10 : 14 : 15
(5) None of these
Solution:
a:b:c= (2 x 5):(5 x 3):(3 7) :.a:b:c= 10 : 15 :21
- If a:b= 1:3,b:c= 2 : then find a:b:c:d =? 5 and c:d= 7:6
(1) 14 : 42 : 105 : 90
(2) 14 : 21 : 150 : 90
(3) 42 : 14 : 105 : 90
(4) 90 : 42 : 105 : 21
(5) None of these
Solution:
a 1 5 7i 6 a:b:c:d= (12 7) : (3 2 7) : (3 5 7) : (3 5 6) a: b:c:d= 14 : 42 : 105 : 90