{"id":4826,"date":"2016-10-20T18:06:31","date_gmt":"2016-10-20T12:36:31","guid":{"rendered":"http:\/\/race4job.com\/blog\/?p=4826"},"modified":"2016-10-21T17:56:56","modified_gmt":"2016-10-21T12:26:56","slug":"quiz-quantitative-aptitude","status":"publish","type":"post","link":"https:\/\/www.race4job.com\/blog\/quiz-quantitative-aptitude\/","title":{"rendered":"Quiz In Quantitative Aptitude"},"content":{"rendered":"

Directions (Q. 1-5) :<\/span> In each of the questions below, two\u00a0equations are provided. On the basis of these you have to
\nfind out the relation between p and q.\u00a0Give answer
\n(1) If P = Q
\n(2) If P > Q
\n(3) If P < Q
\n(4) If P \u2265 Q
\n(5) If P \u2264 Q<\/p>\n

    \n
  1. P2<\/sup> \u2013 P \u2013 12 = 0; \u00a0 \u00a0 \u00a0Q2<\/sup> \u2013 3Q \u2013 28 = 0(5)<\/span><\/li>\n
  2. 2P2<\/sup> \u2013 11P + 5 = 0; \u00a03Q2<\/sup> \u2013 13Q + 4 = 0(2)<\/span><\/li>\n
  3. P2<\/sup> + 7P + 12 = 0; \u00a0 \u00a0Q2<\/sup> + 2Q \u2013 3 = 0(5)<\/span><\/li>\n
  4. 3P + Q = 1; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 8P + 12Q = 5(1)<\/span><\/li>\n
  5. P2<\/sup> + 5P \u2013 14 = 0; \u00a0 \u00a0Q2<\/sup> + 6Q \u2013 7 = 0(4)<\/span><\/li>\n<\/ol>\n

    Directions (Q. 6-10) :<\/span> In each of the questions below, two\u00a0equations are provided. On the basis of these you have to
    \nfind out the relation between p and q.<\/p>\n

    Give answer<\/span>
    \n(1) If P = Q
    \n(2) If P > Q
    \n(3) If P < Q
    \n(4) If P \u2265 Q
    \n(5) If P \u2264 Q<\/p>\n

      \n
    1. P2<\/sup> \u2013 5P + 6 = 0; \u00a0 \u00a0 \u00a0 \u00a0Q2<\/sup> +Q \u2013 6 = 0(4)<\/span><\/li>\n
    2. 2P2<\/sup> + 12P + 16 = 0; \u00a02Q2<\/sup> + 14 Q + 24 = 0(4)<\/span><\/li>\n
    3. 2P2<\/sup> + 48 = 20P; \u00a0 \u00a0 \u00a0 \u00a02Q2<\/sup> + 18 = 12Q(2)<\/span><\/li>\n
    4. Q2<\/sup> + Q = 2; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 P2<\/sup> + 7P + 10 = 0(5)<\/span><\/li>\n
    5. P2<\/sup> + 36 = 12P; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 4Q2<\/sup> + 144 = 48Q(1)<\/span><\/li>\n<\/ol>\n

       <\/p>\n

      EXPLANATIONS<\/span><\/h2>\n

      11.\u00a0<\/span>P2<\/sup> \u2013 P \u2013 12 = 0\u00a0By solving P = \u20134 and 3<\/p>\n

      Q2<\/sup> \u2013 3Q \u2013 28 = 0\u00a0By solving Q = \u20134 and 7
      \n\u2234 P \u2264 Q.<\/p>\n

      12.<\/span> 2P2<\/sup> \u2013 11P + 5 = 0\u00a0By solving P = 1\/2\u00a0and 5
      \n3Q2<\/sup> \u2013 13Q + 4 = 0\u00a0By solving Q =1\/3\u00a0and 4
      \n\u2234 P > Q.<\/p>\n

      13.P2<\/sup><\/span><\/span>+ 7P + 12 = 0
      \n\u21d2 (P + 3) (P + 4) = 0 \u21d2 P = \u20133, \u20134
      \nQ2<\/sup> + 2Q \u2013 3 = 0
      \n\u21d2 (Q \u2013 1) (Q + 3) = 0 \u21d2 Q = 1, \u20133
      \n\u2234 P \u2264 Q.<\/p>\n

      14.<\/span> 3P + Q = 1\u00a08P + 12Q = 5
      \nBy solving P =1\/4\u00a0and Q =1\/4
      \n\u2234 P = Q.<\/p>\n

      15.<\/span> P2<\/sup> + 5P \u2013 14 = 0
      \n\u21d2 (P \u2013 2) (P + 7) = 0 \u21d2 P = 2, \u20137
      \nQ2<\/sup> + 6Q \u2013 7 = 0
      \n\u21d2 (Q \u2013 1) (Q + 7) = 0 \u21d2 Q = 1, \u20137
      \n\u2234 P \u2265 Q.<\/p>\n

      16.<\/span> P2<\/sup> \u2013 5P + 6 = 0
      \nBy solving we get P values as 2 and 3
      \nQ2<\/sup> +Q \u2013 6 = 0
      \nBy solving we get Q values as 2 and \u20133
      \n\u2234 P \u2265 Q.<\/p>\n

      17.<\/span> 2P2<\/sup> + 12P + 16 = 0
      \nBy solving we get P values as \u20134 and \u20132.
      \n2Q2<\/sup> + 14 Q + 24 = 0
      \nBy solving we get Q values as \u20133 and \u20134
      \n\u2234 P \u2265 Q.<\/p>\n

      18.<\/span> 2P2<\/sup> + 48 = 20P
      \nBy solving we get P values as 4 and 6
      \n2Q2<\/sup> + 18 = 12Q
      \nBy solving we get Q values as 3 and 3
      \n\u2234 P > Q.<\/p>\n

      19.Q2<\/sup> <\/span><\/span>\u00a0+ Q = 2
      \nBy solving we get P values as 1 and \u20132
      \nP2<\/sup> + 7P + 10 = 0
      \nBy solving we get Q values as \u20132 and \u20135
      \n\u2234 P \u2264 Q.<\/p>\n

      20.<\/span> P2<\/sup>+ 36\u00a0= 12P
      \nBy solving we get P values as 6 and \u20136
      \n4Q2<\/sup> + 144 = 48Q
      \nBy solving we get Q values as 6 and \u20136
      \n\u2234 P = Q.<\/p>\n","protected":false},"excerpt":{"rendered":"

      Directions (Q. 1-5) : In each of the questions below, two\u00a0equations are provided. On the basis of these you have to find out the relation between p and q.\u00a0Give answer (1) If P = Q (2) If P > Q (3) If P < Q (4) If P \u2265 Q (5) If P \u2264 Q […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-4826","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/posts\/4826","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/comments?post=4826"}],"version-history":[{"count":1,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/posts\/4826\/revisions"}],"predecessor-version":[{"id":4889,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/posts\/4826\/revisions\/4889"}],"wp:attachment":[{"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/media?parent=4826"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/categories?post=4826"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.race4job.com\/blog\/wp-json\/wp\/v2\/tags?post=4826"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}